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How to calculate water tank capacity in liters?

Let us suppose your tank dimensions are 
L = 8ft B = 6 ft D/H = 5 ft
Then your volume of tank will be 
8 x 6 x 5 = 240 ft³


Now 1ft³ = 28.31 liter,
hence, total volume of tank in liter shall be 240 x 28.31 = 6794.4 liter.  That means almost 6800 liter of water can be stored in the tank. 
Here is a quick video to show you How to calculate water tank capacity in liters?

A guide to structural load calculations - 1: Dead Load

How a structure is designed?
Loads are assessed: basic loads are defined as which loads will be coming on the structure.Structure is analyzed upon applying these loads and combination of it.Structure is designed for the results of analysis. Structure is designed to withstand the stresses caused by these forces and its combinations. Structure is designed for the shear force and bending moments found through analysis done based on these load cases and combination. In this article, let us learn the first part of structure design, how to assess the load. How to know as to which load will be coming on the structure in its life span.

Load: every object in universe have some mass, this mass when multiplied with gravity exerts some weight. This weights are creating pressure on the structure they are resting on. These are called loads.

Types of loads:

Dead Load: Self weight of the structure. It can be find by density x volume of the member. Every country has defined densities of different materi…

What are the development lengths of bars for different grade of reinforcement and concrete?

Here are the development lengths of different grade reinforcement bars for different concrete grades. Development lengths are in mm.

1. Development lengths for plain bars of grade Fe250.


2. Development lengths for HYSD bars of grade Fe415.


3. Development lengths for HYSD bars of grade Fe500.





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How to find the mass of reinforcing bar quickly?

Simple way to find the weight of reinforcing bar:

The density of steel is 7850 kg/m³. Now let say you want weight per m. then what will be the formulation? Check this out.
7850(kg/m³) x [pi()/4 x d² ](m²)= mass of the bar per m. (eq. 1) Now resolving this we get 7850 x pi()/4 = 6165.375 right?Putting this into eq. 1
6165.375 (kg/m³) x d² (m²) = mass per m. (eq. 2)
What can be bar diameter? Let say 10mm, 12mm. . . we are used to mm format bar diameters, right? So, let us make formulation to eq. 2 for inputting bar dia as mm. 
1m = 1000mm. => 6165.375 x 10^-6 = 1/162.196
Hence, mass per m of bar = d² (mm²)/162.196.
Now if you want to get mass per feet, then use this relation 1m = 3.281 feet 
Therefore mass of bar per feet = d² (mm²)/(162.196 x 3.281) = d² (mm²)/532.139.
So now onwards, please don’t bother to use d²/162.2 for finding mass of reinforcement. Enjoy.
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